(a)\(I_1=\frac{\epsilon_0 c}{2} E_{01}^2=\frac{(8.85*10^{-12})(3*10^8m/s)}{2}(3,000V/m)^2=11,950W/m^2\)

(a)\(I_2=\frac{\epsilon_0 c}{2} E_{02}^2=\frac{(8.85*10^{-12})(3*10^8m/s)}{2}(4,000V/m)^2=21,240W/m^2\)

(b)\(I_{12}=2\sqrt{I_1 I_2}cos \delta=2\sqrt{(11,950)(21,240)}cos(\frac{\pi}{3}-(\frac{\pi}{5}-\frac{\pi}{6}))=18,720W/m^2\)

(c)\(I=I_1+I_2+I_{12}=11,950+21,240+18,720=51,900W/m^2\)

(d)visibility=\(\frac{I_{max}-I_{min}}{I_{max}+I_{min}}=\frac{(I_1+I_2+2\sqrt{I_1 I_2})-(I_1+I_2-2\sqrt{I_1 I_2})}{(I_1+I_2+2\sqrt{I_1 I_2})+(I_1+I_2-2\sqrt{I_1 I_2})}=\frac{2\sqrt{I_1 I_2}}{I_1+I_2}=\frac{2\sqrt{(11,950)(21,240)}}{11,950+21,240}=0.96\)