The far-field is defined by

$L \gt \gt \frac{area}{\lambda}=\frac{\frac{1}{4} \pi d^2}{\lambda}=\frac{\pi (10^{-3}m)^2}{4(546*10^{-9}m)}=1.4m$

$L=50cm$ is the near-field.

$L=1m$ is the near-field.

$L=5m$ is the far-field.