(a)

\(\sigma=\frac{q}{\pi D^2}=\frac{2.4*10^{-6}C}{\pi (1.3m)^2}=4.5*10^{-7}C/m^2\)

(b)

\(E=\frac{\sigma}{\epsilon_0}=\frac{4.5*10^{-7}C/m^2}{8.85*10^{-12} C^2/N*m^2}=5.1*10^4 N/C\)